Q. 1 Lagi
68/4 + 25/2
_
f(x) = 7(x) + 2(x)
f(3) = ..
68/4 + 25/2
_
f(x) = 7(x) + 2(x)
f(3) = ..
Penjelasan dengan langkah-langkah:
~ No 1
[tex] \sf \frac{68}{4} + \frac{25}{2} = \frac{68}{4} + \frac{25 \times 2}{2 \times 2} [/tex]
[tex] \sf \frac{68}{4} + \frac{50}{4} = \frac{68 + 50}{4} [/tex]
[tex] \sf \frac{118 \div 2}{4 \div 2} = \frac{59}{2} [/tex]
[tex] \bf = 29 \frac{1}{2} [/tex]
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~ No 2
f(x) = 7(x) + 2(x)
f(3) = 7(3) + 2(3)
f(3) = (7 × 3) + (2 × 3)
f(3) = 21 + (2 × 3)
f(3) = 21 + 6
f(3) = 27
Jawaban:
68/4 + 25/2
34/2 + 25/2
(34+25)/2
59/2
= 29 1/2
f(x) = 7(x) + 2(x)
f(3) = ..
penyelesaian :
f(3) = 7(3) + 2(3)
f(3) = 21 + 6
f(3) = 27
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